Question

A is twice older as B. Five years ago A was 3 times as old as B. Find there present age​

Answer 1

Answer:

Age of B = 2 yrs

Age of A = 4 yrs

Step-by-step explanation:

Let the age of B be x.

∴ Age of A = 2x

Five yrs ago 3 times the old as B.

3(2x - 5) = x - 5

6x - 15 = x - 5

6x - x = -5 + 15

5x = 10

x = 2

∴ Age of B = 2 yrs

  Age of A = 4 yrs

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Answer 2

Answer:

A=20,B=10

Step-by-step explanation:

Let present age of A=x years

present age of B=y years

Given that A is twice older as B

x=2y--->equation 1

5 years ago

___________

Age of A=x-5 years

Age of B=y-5 years

Given that A was 3 times as old as B.

x-5=3(y-5)

x-5=3y-15

x=3y-10--->equation 2

Equation 1=Equation 2

2y=3y-10

y=10

x=20

Therefore A present age is 20 years

B present age is 10 years.