Question

A is twice than B ..five years later A will be 9/5 the age of B find the present age of A and B

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Answer 1

Answer:B's age is 20 and A's age is 40

Step by step explanation:

Assume age =x

then A=2x

B=x

because then both will be equal

now

after five years means

A=(x+5)

B=(2x+5)

also,A will be 9/5 times of B

means 9/5(x+5)=(2x+5)

so lets solve for x now

9/5(x+5)=(2x+5)

9x/5+9=(2x+5)

9x/5=2x+5-9

9x/5=2x-4

9x=10x-20

-x=-20

x=20

B=20

A=2×20=40

Thank you