Question

A is two years older than b who is twice as old as



c. If the total of the ages of a,b and c be 27, then how old is b?

Answer 1

Answer:

10 years old

Step-by-step explanation:

Let ages of A, B, C be x, y, z respectively.

Criterion 1: x= y+2, y= 2z

Criterion 2: x+y+z= 27

Substitute y with 2z, as from criterion 1.

Thus, x= 2z+2

Also, x+ 2z +z= 27

Combining the above 2 equations,

(2z+2) +3z= 27

5z+2=27

5z=25

z= 5

Thus, y= 2z= 10

(Also, x= y+2= 10+2= 12.

x+ y+ z= 12+10+5= 27)

Answer 2

SOLUTION ⤵️

Let C's age be x years.

Then, B's age = 2x years and 

A's age = (2x + 2) years

Given, 2x + 2 + 2x + x = 27

⇒ 5x + 2 = 27

⇒ 5x = 27 − 2 = 25

⇒ x = 5

∴ B's age = (2×5) years = 10 years.