Question

a is two years younger than B who is twice as old as C if the total of the ages of A B and C is 28 years then how old is .B​

Answer 1

Answer:

Let the age of C be x

Age of B = 2x

Age of A = 2x - 2

The total age = Rs 28

By the given condition

x+2x+2x-2 = 28

5x- 2 = 28

5x = 28+2 = 30

x = 30/5

= 6

The age of B = 2x = 2*6 = 12 years

hope this helps you!!

Answer 2

Heya❤

According to the question...

A = B - 2 .... (1)

B = 2C .... (2)

A+B+C = 28 ... (3)

Substitute equations 1 and 2 in 3

(B -2) + 2C + C =28

B-2+3C =28

B+3C = 30

B = 30 - 3C ...... (4)

Substitute equation 2 in 4

2C = 30 - 3C

5C = 30

☆C = 6 ☆

Substitute the value of C in 2

B = 2×6

☆B = 12☆

and

A= 12 -2

☆A=10☆

Hence,

☞☞B is 12 years old☜☜

Hope it helps you

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