Question

A is walking towards. B. At one point he sees that there is a distance of 700m between B and him. He
increases his speed by 75% and takes 16 secs to reach her. Had he travelled at his original speed,
how much time would he have taken?

Answer 1

Answer:

Step-by-step explanation:

u of A=x

v of A=x+75/100*x=7x/4           (75/100*x means 75% of x)

s=700m

t=16 sec

vt=s

(7x/4)*16=700

28x=700

x=700/28

x=25 m/s

∴ u=25 m/s

Let time taken if A travelled at original speed be y,

ut=s

xy=s

25*y=700

25y=700

y=700/25

y=28 sec

∴ If A would have travelled by original speed he would have reached b in 28 seconds.