A iton pipe is 21 m long and its exterior diameter is 8cm. If thr thickness of the pipe is 1 cm and the iron weight 8 g/cm³,find the weight of pipe.
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Length of pipe = 21×100 = 2100cm
External diameter = 8cm
Thickness of pipe = 1cm
Internal diameter of pipe = 8-1 =7cm
External radius (R) = 4cm
Imternal radius (r) = 3.5cm
Volume of pipe = πh(R²-r²) = 22/7×2100((4)²-(3.5)²) = 22/7×2100(16-12.25) = 22/7×2100×3.75 = 82.5/14700 = 178.18cm³= 178180g.
Weight of iron of per cm³ = 8g
Weight of iron of 178180cm³ = 8×178180 = 1425.44g
External diameter = 8cm
Thickness of pipe = 1cm
Internal diameter of pipe = 8-1 =7cm
External radius (R) = 4cm
Imternal radius (r) = 3.5cm
Volume of pipe = πh(R²-r²) = 22/7×2100((4)²-(3.5)²) = 22/7×2100(16-12.25) = 22/7×2100×3.75 = 82.5/14700 = 178.18cm³= 178180g.
Weight of iron of per cm³ = 8g
Weight of iron of 178180cm³ = 8×178180 = 1425.44g
architakumari:
Ans. Is given in kg. Not in grm.
right answer
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