Math, asked by mamtagoswami54, 7 months ago

a) j) (p-6)(p + 7) = (p + 3)(p – 11)​

Answers

Answered by siddhimakwana11
1

Answer:

LHS

(p-6)(p+7)

p(p+7)-6(p+7)

p²+7p-6p-42

p²+p-42 ----1

RHS

(p+3)(p-11)

p(p-11)+3(p-11)

p²-11p+3p-33

p²-8p-33 ----2

equating 1 and 2

p²+p-42=p²-8p-33

p-42= -8p-33

p+8p= -33+42

9p=9

p=9/9=1

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