Math, asked by joshitha58, 4 months ago

A jaggery merchant had 8 jaggery
balls with different weights such as ¼ kg ,½kg
¾kg . He called his 3 children
and asked them to share those jaggery
balls equally. How did the children share
it equally among themselves? (Hint: The
number of jaggery balls with the given
weights are 5, 2 and 1 respectively.)​

Answers

Answered by ilikechocolate
7

Step-by-step explanation:

different weights of jaggery balls=1/4kg,1/2kg,3/4kg

total weight of 5 jaggery balls each of 1/4kg=1/4×5=5/4kg

total weight of 2 jaggery balls each of 1/2kg=1/2×2=1kg

total weight of 1 jaggery balls each of 3/4kg=3/4×1=3/4kg

total weight of all jaggery balls=5/4+1+3/4

=3kg

share of each kid=weight of jaggery/no of children

=3/3

=1

each kid will get 1kg of jaggery

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