Question

A jar contains 3Red balls, 4blue balls and 3 green balls. A ball is drawn at random without seeing the colour of the ball. What is the probability that the ball drawn is-
(i) Red in colour?
(ii) Not red in colour?
(iii) Not blue in colour?​

Answer 1

Answer:

i) Red = 3/10

ii) Not red = 7/10

iii) not blue = 4/10 = 2/5

Answer 2

Answer:

i)3/10

ii)7/10

iii)6/10

Step-by-step explanation:

Total No. of balls=(3+3+4)=10

i)No. of Red balls=3

Total No. of Balls=10

Therefore,P(getting a red ball)=3/10

ii)No. of Balls which are not red=(4+3)=7

Total No. of Balls=10

Therefore,P(getting a ball not red in colour)=7/10

iii)No. of Balls which are not blue=(3+3)=6

Total No. of Balls=10

Therefore,P(getting a ball not blue in colour)=6/10