Question

A jar contains 7 3/4 L of milk. After packing the milk in 20 packets of equal capacity, 1/4 L of milk was still left in the jar. Which of the following is the correct process to find the quantity of milk in each of the smaller packets?
(7 3/4 ÷ 20)+18
(7 3/4 − 1/4)÷20
(7 3/4 + 1/4)÷20
(7 3/4 ÷ 1/4)−20

Answer 1

Answer:

answer B is right

$7 \frac{3}{4}l = 20 \times small \: packets \: + \frac{1}{4} l$

$20 \: small \: packets = 7 \frac{3}{4} - \frac{1}{4}$

$1small \: packet = (7 \frac{3}{4} - \frac{1}{4} ) \div 20$