Chemistry, asked by shubhamhote6467, 1 year ago

A jar contains a mixture of apple juice and vinegar in the ratio of 3: 2 respectively. some quantity ofmixture was taken out and 8 litre vinegar was added to it if the resultant quantity of vinegar in the mixturewas 4 litre more than the initial quantity of vinegar, what was the quantity of mixture taken out from the jar ?

Answers

Answered by danielochich
2
Let the original volume = x

volume of apple = 3/5x

volume of vinegar = 2/5x

If y litres is removed, the remaining volume = x-y

volume of apple = 3/5(x-y)

volume pf vinegar = 2/5(x-y)

8 litres of vinegar added

new volume of vinegar = 2/5(x-y) + 8


The resultant quantity of vinegar in the mixture was 4 litre more than the initial quantity of vinegar


2/5(x-y) + 8 = 2/5x + 4

2/5x - 2/5y + 8 = 2/5x + 4

-2/5y = -4

y = (4x5)/2


 y = 10


The quantity of mixture taken out of the jar = 10 litres
Answered by Anonymous
35

Answer:

Explanation:

Let the original volume = x

volume of apple = 3/5x

volume of vinegar = 2/5x

If y litres is removed, the remaining volume = x-y

volume of apple = 3/5(x-y)

volume pf vinegar = 2/5(x-y)

8 litres of vinegar added

new volume of vinegar = 2/5(x-y) + 8

The resultant quantity of vinegar in the mixture was 4 litre more than the initial quantity of vinegar

2/5(x-y) + 8 = 2/5x + 4

2/5x - 2/5y + 8 = 2/5x + 4

-2/5y = -4

y = (4x5)/2

y = 10

The quantity of mixture taken out of the jar = 10 litres

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