A jar contains a mixture of apple juice and vinegar in the ratio of 3: 2 respectively. some quantity ofmixture was taken out and 8 litre vinegar was added to it if the resultant quantity of vinegar in the mixturewas 4 litre more than the initial quantity of vinegar, what was the quantity of mixture taken out from the jar ?
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Answered by
2
Let the original volume = x
volume of apple = 3/5x
volume of vinegar = 2/5x
If y litres is removed, the remaining volume = x-y
volume of apple = 3/5(x-y)
volume pf vinegar = 2/5(x-y)
8 litres of vinegar added
new volume of vinegar = 2/5(x-y) + 8
The resultant quantity of vinegar in the mixture was 4 litre more than the initial quantity of vinegar
2/5(x-y) + 8 = 2/5x + 4
2/5x - 2/5y + 8 = 2/5x + 4
-2/5y = -4
y = (4x5)/2
y = 10
The quantity of mixture taken out of the jar = 10 litres
volume of apple = 3/5x
volume of vinegar = 2/5x
If y litres is removed, the remaining volume = x-y
volume of apple = 3/5(x-y)
volume pf vinegar = 2/5(x-y)
8 litres of vinegar added
new volume of vinegar = 2/5(x-y) + 8
The resultant quantity of vinegar in the mixture was 4 litre more than the initial quantity of vinegar
2/5(x-y) + 8 = 2/5x + 4
2/5x - 2/5y + 8 = 2/5x + 4
-2/5y = -4
y = (4x5)/2
y = 10
The quantity of mixture taken out of the jar = 10 litres
Answered by
35
Answer:
Explanation:
Let the original volume = x
volume of apple = 3/5x
volume of vinegar = 2/5x
If y litres is removed, the remaining volume = x-y
volume of apple = 3/5(x-y)
volume pf vinegar = 2/5(x-y)
8 litres of vinegar added
new volume of vinegar = 2/5(x-y) + 8
The resultant quantity of vinegar in the mixture was 4 litre more than the initial quantity of vinegar
2/5(x-y) + 8 = 2/5x + 4
2/5x - 2/5y + 8 = 2/5x + 4
-2/5y = -4
y = (4x5)/2
y = 10
The quantity of mixture taken out of the jar = 10 litres
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