Question

A jar contains a mixture of liquids a and b in the ratio 3:2. When 20 litres of the mixture is taken our and replaced by 20 litre of liquid b, the ratio changes to 1:4. How many litres of liquid a was there initially present in the jar

Answer 1

Answer:

Let a be the amount of liquids 'a' initially and b be the amount of liquids 'b' initially, all in litres. Then:

$\frac{a-\left(\frac{3}{5}\cdot 20\right)}{b-\left(\frac{2}{5}\cdot 20\right)+20}=\frac{1}{4}$ (1)

$\frac{a}{b}=\frac{3}{2}$ (2)

Solving (1) and (2) simultaneously yields the following results:

a=18, b=12

∴ Total liquids present originally is a+b=18+12=30

Hope this helps :)

Step-by-step explanation: