A jar contains a mixture of milk and water in the ratio of 3:1. Now, 1/25 of the mixture is taken out and 24 litres water is added to it. If the resultant ratio of milk to water in the jar was 2:1, what was the initial quantity of mixture in the jar? (in litres)
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Answer:
milk=3x=75/2 lt
water=x 25/2 lt
Step-by-step explanation:
ratio=3:1
let the common ratio be x
hence, milk=3x qnd water=x
mixture=3x+x=4x
1/25mixture is taken out
thus, milk left=(24/25)×(3x)
water left=(24/25)×(x)
finally,
water = (24x/25)+24
A.T.P.
(24/25)×3x / (24/25)×x + 24 = 2/1
(24/25)3x / (24x+600)/25 = 2/1
72x×25 / 24x+600 = 2/1
1800=48x + 1200
x=600/48=25/2
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