Math, asked by srsrs3959, 10 months ago

A jar contains a mixture of milk and water in the ratio of 3:1. Now, 1/25 of the mixture is taken out and 24 litres water is added to it. If the resultant ratio of milk to water in the jar was 2:1, what was the initial quantity of mixture in the jar? (in litres)

Answers

Answered by acecloud
4

Answer:

milk=3x=75/2 lt

water=x 25/2 lt

Step-by-step explanation:

ratio=3:1

let the common ratio be x

hence, milk=3x qnd water=x

mixture=3x+x=4x

1/25mixture is taken out

thus, milk left=(24/25)×(3x)

water left=(24/25)×(x)

finally,

water = (24x/25)+24

A.T.P.

(24/25)×3x / (24/25)×x + 24 = 2/1

(24/25)3x / (24x+600)/25 = 2/1

72x×25 / 24x+600 = 2/1

1800=48x + 1200

x=600/48=25/2

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