Math, asked by mobilessearch4941, 1 year ago

A jar contains a mixture of two liquid a and b in the ratio 4:1. When 10 liter of mixture is replaced with liquid b the ratio becomes 2:3. The volume of liquid present in the jar?

Answers

Answered by Anmol18125
1
when any quantity of mixture is taken out from the mixture then the ratio of the remaining mixture remains the same = 4 : 1



Now mixture is taken out and liquid B is added. So, make A proportion equal.

5 units = 10 ltr. 

1 unit = 2 ltr. 

Quantity of solution = 4 + 6 

= 10 units 

= 10×210×2 = 20 litres 

Initial ratio of 

A : B

4 : 1 

4x + x = 20 ltr. 

x = 4 ltr. 

A = 4×44×4 = 16 ltr. 

B = 4×14×1 = 4 ltr.
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