A jar contains a mixture of two liquid a and b in the ratio 4:1. When 10 liter of mixture is replaced with liquid b the ratio becomes 2:3. The volume of liquid present in the jar?
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when any quantity of mixture is taken out from the mixture then the ratio of the remaining mixture remains the same = 4 : 1
Now mixture is taken out and liquid B is added. So, make A proportion equal.
5 units = 10 ltr.
1 unit = 2 ltr.
Quantity of solution = 4 + 6
= 10 units
= 10×210×2 = 20 litres
Initial ratio of
A : B
4 : 1
4x + x = 20 ltr.
x = 4 ltr.
A = 4×44×4 = 16 ltr.
B = 4×14×1 = 4 ltr.
Now mixture is taken out and liquid B is added. So, make A proportion equal.
5 units = 10 ltr.
1 unit = 2 ltr.
Quantity of solution = 4 + 6
= 10 units
= 10×210×2 = 20 litres
Initial ratio of
A : B
4 : 1
4x + x = 20 ltr.
x = 4 ltr.
A = 4×44×4 = 16 ltr.
B = 4×14×1 = 4 ltr.
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