Question

A jar contains a mixture of two liquids A and B in the ratio 4: 1. When 10L of mixture is replaced with liquid B, how many liters of liquid A was present in the jar earlier??

Answer 1

10 litres of mixture that is replaced will contain 8 litres of A and 2 litres of B (as A:B = 4:1)

Let the initial volume of the mixture be 4K + 1K = 5K

So by condition ,

[ 4K-8 ]/ [ K-2+10 ] = 2/3

Solve for K which is K = 4

So initial volume of liquid A = 4K = 16 litres

Hope this clarifies