A jar cotains 81 balls each of which is red ,blue ,green .the probability of selecting a red ball is 1/3 and that of blue is 4/9 . How many green balls does the jar contains
Answers
Given : A jar cotains 81 balls each of which is red ,blue ,green .
the probability of selecting a red ball is 1/3 and that of blue is 4/9 .
To Find : How many green balls does the jar contains
Solution:
probability of selecting a red ball = Number of red balls/ Total balls
=> 1/3 = red ball /81
=> red balls = 27
probability of selecting a blue ball = Number of blue balls/ Total balls
=>4/9 = blue/81
=> blue balls =36
Red Balls + blue balls +green balls = Total
=> 27 + 36 + green balls = 81
=> green balls = 18
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Answer:
We know,
P(getting red ball) = 1/4
P(getting blue ball) = 1/3
Let the no. of balls = x
Therefore, P(getting orange ball) = 10/x
We know,
P(getting red ball) + P(getting blue ball) + P(getting orange ball) = 1
⇒1/4 + 1/3 + 10/x = 1
⇒10/x = 1 -1/4 -1/3
⇒10/x = 1 - 7/12
⇒10/x = 5/12
⇒10 * 12 = 5 * x
⇒x = 24
Therefore, the no. of balls = x
= 24
Hope This helps :)