Question

a jar full of liquid contains 30% water. a part of this liquid is replaced by another liquid containing 17% water. the percentage of water in the resulting mixture is 24%. how much liquid is actua

Answer 1

Answer:

hii

Step-by-step explanation:

Water in first liquid =20%

Water in second liquid =35%

10 part of first liquid and 4 part of second liquid are added to form a new liquid.

So, required percentage of water in new liquid,

=

14

2+(7/5)

×100

=

7

170

%

Answer 2

The quantity of liquid replaced is  0.538.

Step-by-step explanation:

Given:

A jar is full of liquid which contains % 30 water.

A part of this liquid is replaced by another liquid containing %17 water.

The % of water in the resulting mixture is % 24.

To Find:

The quantity of liquid is replaced.

Formula Used:

Quantity of water in 1st Jar / Quantity of  water in 2nd Jar = ( Strength of water  in 1 st Jar -  Mean  Strength) / (Mean  Strength –  Strength of water  in 2 nd  Jar)--------------------------- formula no.01

The above is per the rule of the allegation.

Solution:

As given- A jar full of liquid which contains 0 water.

A part of this liquid is replaced by another liquid containing water.

The % of water in the resulting mixture is % 24.

Strength of water  in 1 st  Jar = %30

Strength of water in 2 nd  Jar = % 17

Mean  Strength= %24

Applying formula no.01.

$\frac{Quantity \ of\ liquid \ in \ 1st \ Jar}{Quantity \ of\ liquid \ in \ 2 nd \ Jar} =\frac{(30-24)}{(24-17)}$

                                           $=\frac{6}{7}$                                                            

The quantity of liquid replaced $=\frac{7}{13} =0.538$

Thus, the quantity of liquid replaced is  0.538.

Correct Question

A jar full of liquid which contains % 30 water. a part of this liquid is replaced by another liquid containing water. the % of water in the resulting mixture is % 24. How much liquid is replaced?