A jar full of whisky contains 40% of alcohol. A part of whisky is replaced by another containing 19% of alcohol and now new alcohol be 26%, find the quantity of whisky replaced.
Answers
Solution:
Amount of Alcohol in jar which contains full of whisky =40%
So,Amount of water = 100-40=60%
It is also, given that a part of whisky is replaced by another containing 19% of alcohol and now new alcohol be 26%.
The Whisky which has replaced the Whisky in the Jar
Amount of Alcohol =19%
Amount of Water =100-19=81%
In new Whisky
Amount of Alcohol =26 %
Amount of Water = 100 -26=74%
Writing in terms of equation with the help of variable ,x and y
40%x +19%y=26%
60% x + 81%y=74%
1.40 x +19 y=26-----×3
2.60 x + 81 y= 74-------×2
1.→120 x + 57 y = 78
2.→120 x + 162 y = 148
(1) - (2)
-105 y = -70
Substituting value of ,y in equation (2)
So, in the beginning Amount of Whisky that is amount of water in the jar =60%
Amount of Alcohol in the beginning in the Jar =40%
Amount of Whisky Replaced
Amount of alcohol in the Whisky
%
Amount of water in the Whisky
%
Answer:
2/3 of whisky is replaced
Step-by-step explanation:
Let say Jar Volume = 100 V ml
ALCOHOL= 40V
Non-Alcohol = 60V
Let say X ml is replaced
so Reduced Alcohol = 0.4X
Reduced non alcohol = 0.6X
Added Alcohol = 0.19X
Added non-alcohol = 0.81X
New Alcohol = 40V - 0.4X + 0.19X = 40V - 0.21X
New non-alcohol = 60V - 0.6X + 0.81X = 60V + 0.21X
New Alcohol % = (40V - 0.21X)/100V * 100
(40V - 0.21X)/100V * 100 = 26
=> 40V - 0.21X = 26V
=> 14V = 0.21X
=> X = 14V/(0.21)
=> X = 200V/3
=> X = (2/3) 100V
2/3 of whisky is replaced