Question

A jar of whiskey originally contained alcohol at 44%. A part of this whiskey is replaced by another drink containing alcohol at 20%.
If the resulting mixture contains alcohol at 24%, what fraction of
whiskey was replaced?

Answer 1

Answer:

Whiskeys must also have a certain alcohol percentage in them during and after the production process. For example, Scotch Whisky must be distilled at no more than 94.8% ABV (190 US proof) and the finished product must be at least 40% ABV (80 US proof).

Step-by-step explanation:

Answer 2

The answer is 4/5

GIVEN

A jar of whiskey originally contained alcohol at 44%. A part of this whiskey is replaced by another drink containing alcohol at 20%.If the resulting mixture contains alcohol at 24%.

TO FIND

The fraction of whiskey replaced.

SOLUTION

We can simply solve the above problem as follows;

Percentage volume of alcohol in dearer quantity = 40%

Percentage Volume of alcohol in cheaper quantity = 20%

Mean percentage of Alcohol = 24%

According to law of Allegation;

Cheaper quantity/Dearer quantity = (Dear price - mean)/(mean - cheaper price)

= (44-24)/(24-20)

= 20/5

Cheaper quantity/dearer = 4/1

This means, The jar gas 5 parts of alcohol in which part of cheaper quality of alcohol = 4 parts

Part of dearer quantity alcohol = 1 part.

Quantity of cheaper drink in the jar = 4/5 parts

Quantity of dearer drink in the jar = 1/5 parts

Quantity of cheaper drink in the jar = Quantity of drink replaced = 4/5

Hence, The answer is 4/5

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