Question

A Jeep starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of    110m. Determine the acceleration of the Jeep.​

Answer 1

Hi.....

Given -

Time = 5.21 s

U = 0

S = 110m

So from equation

$s = ut + \frac{1}{2} a {t}^{2}$

$110 = 0 \times 5.21 + \frac{1}{2} a \times {5.21}^{2}$

$\frac{1}{2} a = \frac{110}{27.14}$

$a = \frac{220}{27.14}$

$a = 8.10 \frac{m}{ {s}^{2} }$

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