A jeep starts from rest and attains a speed of 40 kilometre per hour in 10 minutes. The uniform acceleration will be
Answers
Answered by
5
Explanation:
u=0
v=40.1000/60m/s
t=600s
a= v-u/t
a= 40000/3600.60 m/s^2
Answered by
1
Answer:
1.85 /s
Explanation:
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