A jeep starts from rest and attains a speed of
40 km h in 10 minutes. The uniform
acceleration will be
(1) 40 km h?
(2) 400 km h
(3) 240 km h
(4) 2400 ms
-2.
-2
- 2
Answers
Answered by
1
Answer:
v=40km/h=11.11m/s=1111cm/s
t=10mins=600secs
u=0
a=
t
v−u
=
600
1111
=1.85cm/s
2
Explanation:
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Answered by
2
Answer:
2
Explanation:
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