Question

A jeep starts from rest with an acceleration of 2 m/s2. It can have a maximum speed of 20 m/s. Find the

displacement of the jeep in 20 seconds.​

Answer 1

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GIVEN:

Initial velocity,u = 0 m/s

Final velocity, v = 20m/s

acceleration,a = 2m/s

Time ,t = 20 seconds

To Find :

Displacement of the jeep

Formula:

s = ut+1/2at^2

s = 0+20 + 1/2×2×(20)^2

s = 0 + 1/2×2×400

s = 0 + 1/2 ×800

s = 400

Displacement of the jeep = 400m