Question

A jeep starts from rest with an acceleration of 2 m/s2. It can have a maximum speed of 20 m/s. Find the

distance covered by the jeep in 20 seconds.​

Answer 1

Answer:

Distance covered by the Jeep is 800m

Explanation:

S = ut + 1/2at^2

u = 20 m/s

t = 20 sec

a = 2 m/s^2

s = (20)20 + 1/2(2)(20)^2

= 400 + 2/2(400)

= 400 + 400

= 800m

Answer 2

Answer:

400 m

Explanation:

Given,

initial velocity (u) = 0 (because it starts from rest)

acceleration (a) = 2 m/s^2

time taken (t) = 20 seconds

we need to find, displacement (S) of jeep in 20 seconds

From the 3rd equation we know that,

$S = ut + \frac{1}{2} at^{2}$

Substitute values in the equation

S = 0(20) + 1/2 x 2(20)^2

S = 0 +400

S = 400 m//

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