A jeep starts from the state of rest.If its velocity becomes 60km/hr in 5 minutes.Then what is the distance covered by the jeep?
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acceleration= velocity/time
60km/hr = 60 km /60 mins = 1km/min so accn = 1km/5= 1000m/5 = 200m/m
v²= u²+2as
(1000)² = 0²+ 2 x 200 x s
(1000)²/400= s
2500m
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