Question

A jeep starts from the state of rest.If its velocity becomes 60km/hr in 5 minutes.Then what is the distance covered by the jeep?​

Answer 1

acceleration= velocity/time

60km/hr = 60 km /60 mins = 1km/min so accn = 1km/5= 1000m/5 = 200m/m

v²= u²+2as

(1000)² = 0²+ 2 x 200 x s

(1000)²/400= s

2500m