Question

A jet aeroplane travelling at the speed of 500km h-1 ejects its products of combustion at the speed of 1500kmh-1

Answer 1

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Speed of the jet airplane, vjet = 500 km/h

Relative speed of its products of combustion with respect to the plane,

vsmoke = – 1500 km/h

Speed of its products of combustion with respect to the ground = v′smoke

Relative speed of its products of combustion with respect to the airplane,

vsmoke = v′smoke – vjet

– 1500 = v′smoke – 500

v′smoke = – 1000 km/h

The negative sign indicates that the direction of its products of combustion is opposite to the direction of motion of the jet airplane.

Answer 2

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Speed of the jet airplane,

v(jet )= 500 km/h

Relative speed of its products of combustion with respect to the plane,

v(smoke) = – 1500 km/h

Speed of its products of combustion with respect to the ground = v′(smoke) Relative speed of its products of combustion with respect to the airplane,

v(smoke) = v′(smoke) – v(jet)

1500 = v′(smoke )– 500

v′(smoke )= – 1000 km/h

The negative sign indicates that the direction of its products of combustion is opposite to the direction of motion of the jet airplane.

I hope, this will help you

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