Question

A jet airplane travelling at the speed of 500 km h⁻¹ ejects its products of combustion at the speed of 1500 km h⁻¹ relative to the jet plane. What is the speed of the later with respect to an observer on the ground?​

Answer 1

Answer:

Explanation:

Relative velocity

V

A/B

​

=v

A

​

−v

B

​

given

V

A/B

​

=1500Km/h

v

A

​

−v

B

​

=1500

v

A

​

−(−500)=1500

Since the velocity of combustion products and plane are in opposite directions

V

A

​

=