Question

A jet cruising at a speed of 1000 km/hr ejects hot air in the opposite direction. If the speed of hot air with respect to Jet is 800 km/hr, then find its speed with respect to ground​

Answer 1

AnswEr :

• Speed of products of combustion with respect to the ground = - 200km/h

Given :

• Velocity of jet(Vj) = 1000 km/h

• Velocity of hot air(Smoke, Vs) = 800 km/h

To Find :

• Speed of products of combustion with respect to the ground = ?

Solution :

According to the question,

Relative speed of the products of combustion with respect to the airplane(Vg) would be,

➝ Vs = Vg - Vj

➝ Vg = -Vj + Vs

➝ Vg = -1000 + 800

➝ Vg = -200 km/h

Here, the minus sign indicates the direction of the products of combustion !!

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$\dag \ {\large{\underline{\underline{\sf{\orange{Additional \ Information :}}}}}}$

• Formula for speed is ,

• Speed = Distance/Time

• Speed is a scalar quantity.

• Velocity tells the direction of the movement of the body or an object .

• Velocity is a vector quantity .

• Velocity is given by v = Δs/Δt .

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Answer 2

Answer:

200km

Explanation: