A jet of water with area of cross section 2cm^2 strikes a wall at an angle 60 degrees to the normal and rebounds elastically from the wall with the same speed. If the speed of water in the jet is 10m/s, then find the force acting on the wall.
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Answered by
0
Answer:
hi i need some points please help me
Answered by
0
Answer:
Answer
Correct option is
B
86.4N
F =
dt
dP
=
dt
2dmVcos60
o
=
dt
2(ρAdx)Vcos60
o
= 2ρAV
2
cos60
o
= 10
3
×6×10
−4
×12
2
=86.4N
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