Question

A jet plan travelling at the speed of 450 km/h eject the burnt gas with the speed of 1200 km/h relative to jet plane. find the speed of burnt gas with respect to a man standing on a ground

Answer 1

jet speed=450/h
burnt gas speed relative to jet=1200km/h
so speed of gas relative to a man on the ground= 450+1200km/h
=1650

Answer 2

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Speed of the jet airplane, v jet = 500 km/h

Relative speed of its products of combustion with respect to the plane,

v smoke = – 1500 km/h

Speed of its products of combustion with respect to the ground = v′smoke

Relative speed of its products of combustion with respect to the airplane,

vsmoke = v′smoke – vjet

1500 = v′smoke – 500

v′smoke = – 1000 km/h

The negative sign indicates that the direction of its products of combustion is opposite to the direction of motion of the jet airplane.

I hope, this will help you

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