Question

a jet plane covers 4500 km in some time if the regular speedis decreased y 150 km/h it takes one and half hour more to complete the journey.find the original speed of the jet plan​

Answer 1

Question:

A jet plane covers 4500 km in some time if the regular speed is decreased y 150 km/h it takes one and half hour more to complete the journey.find the original speed of the jet plan.

Step By Step Solution:

• Let's assume the original speed to be "x" km/hr.

Distance covered: 4500 km

The speed decreases by 150km/hr.

• Thus, new speed = (x - 150) km/hr.

• Thus, time taken = ($\tt \frac{4500}{x}$) hrs

• Time taken ( with decreased speed ) = ($\tt \frac{4500}{x} - 150$) km/hr.

According to the quest,

$⇉ \tt \frac{(4500}{x} - 150 - \frac{4500}{x} = \frac{ 3}{2}$

$⇉\tt \frac{4500 (x - x + 150) }{ x(x - 150) }= \frac{3}{2}$

$⇉ \tt 4500 (150) × \frac {2}{3 }= x(x - 150)$

⇉1500 × 150 × 2 = x² - 150x

⇉ 450000 = x² - 150x

⇉x² - 150x - 450000 = 0

⇉ x² - 750x + 600x - 450000 = 0

⇉x(x - 750) + 600(x - 750) = 0

⇉ (x + 600) (x - 750) = 0

⇉x = -600 or x = 750

As, Speed cannot be negative.

So, x = 750 km/hr.

The original speed of the jet is 750 km/hr.

$\huge \bold{@ParkStanley}$

Answer 2

Answer:

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