A jet plane covers 4500 km in some time. If the regular speed is decreased by 150 km/hr it take one and a half hour more to complete the journey. find original speed of jet plane
Answers
If the jet takes 1 and half hr more for a distance of 4500 km by decreasing the regular speed by 150 km/hr then the original speed of the jet plane is 750 km/hr.
Step-by-step explanation:
Required Formula:
- Time = [Distance] / [Speed]
Let the original speed of the jet plane be “s” km/hr.
The distance covered by the jet plane = 4500 km
The new speed after decreasing by 150 km/hr = [s - 150] km/hr
Therefore,
Time taken with the original speed = [4500/s] hr
And,
Time taken with the decreased speed = [800/(s-150)] hr
According to the question, we have,
[4500/(s-150)] - [4500/s] = 1 ½ = 3/2
⇒ 4500 [(s-s+150) / s(s-150)] = 3/2
⇒ 1500 * 150 * 2 = s(s-150)
⇒ s² - 150s = 450000
⇒ s² - 150s – 450000 = 0
⇒ s² + 750s + 600s – 450000
⇒ s(s-750) + 600(s-750) = 0
⇒ (s-750)(s+600) = 0
⇒ s = -600 or 750
Neglecting the negative value
⇒ s = 750 km/hr
Thus, the original speed of the jet plane is 750 km/hr.
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