Question

A jet plane covers 4500km in so me time. it the regular speed is decreased by 150 km/h. It takes one & halt hollt more to complore the journey . get Find the original speed plane
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Answer 1

Answer:

Let the original speed be s, then the time taken to cover 4500 km will be t=4500/s

Now the speed is decreased by 150, so the new speed is s-150 and new time is t+(3/2)

t+(3/2)=4500/(s-150)

In this equation put t=4500/s

4500/s +(3/2)=4500/(s-150)

(9000+3s)=9000/(s-150)

(s-150)(9000+3s)=9000

3s^2-450s+9000s-9000×150=9000

3s^2+8550s-9000×151=0

This is a quadratic equation in s. Find the value of s by solving it by midterm splitting. You will get two values one + and one negative. choose the + one. That is the answer.