A jet plane is flying at a height of 30,000 ft. It ascends at the rate of 100 ft/sec for 20 seconds and then descends at the rate of 150 ft/sec for 15 seconds. How far is it now relative to its initial height?
+150 ft
plus 150 ft
−150 ft
negative 150 ft
+250 ft
plus 250 ft
−250 ft
negative 250 ft
None of these
Answers
Answered by
20
Answer:
hey mate this is your answer
Step-by-step explanation:
if you are satisfied with my answer please mark me as brainlest
Attachments:
Answered by
7
Answer:
250 ft
Step-by-step explanation:
Initial height = 30,000
Rate of Ascending = 100 ft/sec for 20 seconds
Height now after ascending = 30,000 + 100 x 20
= 30,000 + 2000
= 32,000 ft
Rate of Descending = 150 ft/sec for 15 seconds
Height now after descending = 32,000 - 150 x 15
= 32,000 - 2250
= 29,750 ft
height from it's initial height = 30,000 - 29,750
= 250 ft
Similar questions