Math, asked by rajivtgss, 3 months ago

A jet plane is flying at a height of 30,000 ft. It ascends at the rate of 100 ft/sec for 20 seconds and then descends at the rate of 150 ft/sec for 15 seconds. How far is it now relative to its initial height?

+150 ft
plus 150 ft

−150 ft
negative 150 ft

+250 ft
plus 250 ft

−250 ft
negative 250 ft

None of these

Answers

Answered by sasi273
20

Answer:

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Step-by-step explanation:

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Attachments:
Answered by Abhiram1221
7

Answer:

250 ft

Step-by-step explanation:

Initial height = 30,000

Rate of Ascending = 100 ft/sec for 20 seconds

Height now after ascending = 30,000 + 100 x 20

                                               = 30,000 + 2000

                                               = 32,000 ft

Rate of Descending = 150 ft/sec for 15 seconds

Height now after descending = 32,000 - 150 x 15

                                               = 32,000 - 2250

                                               = 29,750 ft

height from it's initial height = 30,000 - 29,750

                                               = 250 ft

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