A jet plane is flying west at the speed of 1,200 kmh"¹ parallel to the surface of earth. What is the voltage difference developed between the ends of its wing 24 m long, if the earth's magnetic field at the location has a magnitude of 4.92 x 10"⁴T and angle of dip is 30°?
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Given :
Speed of jet plane =v= 1200 km/h
= 1200x5/18 m/s
l=Distance= 24m
earth's magnetic field=B= 4.92 x 10 ⁻⁴T
angle of dip=δ=30°
Formula to be used :
e= BVl=Bsinδvl
e=[4.92 x 10 ⁻⁴sin30°x1200x5x24 ]/18
=4.92 x 10 ⁻⁴ x1200x5x24x1/18 x 2
=19680x 10 ⁻⁴ V
=1.968V
∴voltage difference developed between the ends of its wing is 1.968V
Answered by
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e = B v l cosФ
v = 500/3 m/s ; B = 4.92 X 10⁻⁴ T ; l = 24 m ; cosФ = cos30 = √3 /2
e = 4.92 X 10⁻⁴ X 500 X 24 X √3 / 6
e = 5.904 V
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