A jet plane is moving vertically upward with speed 300 kilometre per hour it is rejecting product of combustion with speed 1200 kilometre per hour with respect to find out actual product of combustion.
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Answer:
900 km per hour
Explanation:
Given
Speed of moving jet plane = 300 kilometre per hour
Speed of ejection product combustion = 1200 kilometre per hour with respect to itself
A.T.Q.
=> Vr = Vj + VP
=> 1200 = 300 + Vp
=> Vp = 900 km/ h
Hence
Speed of combustion product is 900 km per hour.
Answered by
0
900 km per hour is the answer
Speed of moving jet plane = 300 kilometre per hour
Speed of ejection product combustion = 1200 kilometre per hour with respect to itself
A.T.Q.
=> Vr = Vj + VP
=> 1200 = 300 + Vp
=> Vp = 900 km/ h
Explanation:hope this helps!!
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