A jet plane is moving vertically upward with speed 300 kilometre per hour it is rejecting product of combustion with speed 1200 kilometre per hour with respect to find out actual product of combustion.
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Explanation:
Given
Speed of moving jet plane = 300 kilometre per hour
Speed of ejection product combustion = 1200 kilometre per hour with respect to itself
A.T.Q.
By Concept of relative speed
=> Vr = Vj + VP
=> 1200 = 300 + Vp
=> Vp = 900 km/ h
Hence
Speed of combustion product is 900 km per hour.
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