A jet plane is traveling horizontally at
speed of 1800 km/hour. What is potential difference
developed between the tips of its wings if wing
spam is 25cm ? Earths magnetic field at the
location is o.4 gauss and the angle of dip
is
30°
A 25mV
B. 250mV
C. 500mV
D. 2.5V
E. 5V
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Answer:
Speed of the jet plane towards west = 1800 km/h
In m/s, speed of the jet plane towards west,v = 1800 × 5/18 = 500 m/s
Length of the span of the jet plane = 25 m
Magnetic field = 5 × 10^-4 T
Dip angle =30°
The vertical component of Earth’s magnetic field can be calculated as follows: Bv= B sinδ
Bv= 5 × 10^-4 T × sin30°
⇒ Bv= 5 × 10^-4 T × 1/2
∴ Bv = 2.5 × 10^-4 Tesla
The voltage difference developed between the ends of the jet can be calculated using the formula:
e = (Bv) × l × v
e =2.5×10^-4 T× 25m × 500m/sec
e = 3.125 V
∴ the voltage difference developed between the ends of the wings is approximately 3V.
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