Question

A jet plane is travelling towards west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the wing having a span of 25 m, if the Earth’s magnetic field at the location has a magnitude of 5 × 10–4 T and the dip angle is 30°......

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Answer 1

Answer:

Speed =

1800k/h

=1800× (5/18)

=500m/s

L = distance between the ends of the wings = 25m

NOW

By the given condition

b = 5×10^−4 T

θ=30°

Here motional emf (e)

= Bvl ( where B =vertical componet of the earth magnetic field)

So

e = 5×10^−4 × sin30° × 500 × 25 = 3.1V

Hence the voltage difference developed between the ends is 3.1 V

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Answer 2

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Speed of the jet plane, v = 1800 km/h = 500 m/s

Wing spanof jet plane, l = 25 m

Earth’s magnetic field strength, B = 5.0 × 10−4 T

Angle of dip = 30°

Vertical component of Earth’s magnetic field,

BV = B sin

= 5 × 10−4 sin 30°

= 2.5 × 10−4 T

Voltage difference between the ends of the wing can be calculated as:

e = (BV) × l × v

= 2.5 × 10−4 × 25 × 500

= 3.125 V

Hence, the voltage difference developed between the ends of the wings is

3.125 V.