A jet plane is travelling towards west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the wing having a span of 25 m, if the Earth’s magnetic field at the location has a magnitude of 5 × 10–4 T and the dip angle is 30°......
Answers
Speed of the jet plane, v = 1800 km/h = 500 m/s
Wing spanof jet plane, l = 25 m
Earth’s magnetic field strength, B = 5.0 × 10−4 T
Angle of dip = 30°
Vertical component of Earth’s magnetic field,
BV = B sin
= 5 × 10−4 sin 30°
= 2.5 × 10−4 T
Voltage difference between the ends of the wing can be calculated as:
e = (BV) × l × v
= 2.5 × 10−4 × 25 × 500
= 3.125 V
Hence, the voltage difference developed between the ends of the wings is
3.125 V.
SOLUTION ::
Speed =
1800k/h
=1800× (5/18) m/s
=500m/s
L = distance between the ends of the wings = 25m
NOW
By the given condition
b = 5×10^−4 T
θ=30°
Here motional emf (e)
= Bvl ( where B =vertical componet of the earth magnetic field)
So
e = 5×10^−4 × sin30° × 500 × 25 = 3.1V
Hence the voltage difference developed between the ends is 3.1 V
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