Question

A jet plane starts from rest with an acceleration of 3ms-2 and makes a run for 35s before taking off. What is the minimum length of the runway and what is the velocity of the jet at take off?.


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Answer 1

Answer:

?ajet plant stsrt from rest with

Answer 2

Answer:

velocity=70m/s, minimum length=1225m

Step-by-step explanation:

u=0m/s

a=2m$s^{-2}$

t=35s

Using v=u+at

v=0+2*35

v=70m/s before take off

Using s=ut+1/2*a*$t^{2}$

s=0*35+1/2*2*$35^{2}$

s=1225m

So the minimum length of the runway required is 1225m