A jet plane starts from rest with an acceleration of 3ms-2 and makes a run for 35s before taking off. What is the minimum length of the runway and what is the velocity of the jet at take off?
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hi ji
Answers
Answered by
8
Given :
Initial velocity (u) = 0m/s
Time taken (t) = 35s
To find :
Distance (s)
Final velocity (v)
Formula used:
S = ut + 1/2 × at²
v = u + at
Solution :
S = 0(35) + 1/2 × 3(35)²
S = 0 + 1/2 × 3(1225)
S = 0 + 1/2 × 3675
∴ S = 1837.5 meters
___________________
v = u + at
v = 0 + 3(35)
∴ v = 105 m/s
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