Question

A jet plane starts from rest with an acceleration of 3ms-2 and makes a run for 35s before taking off. What is the minimum length of the runway and what is the velocity of the jet at take off?.

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Answer 1

Answer:

Velocity of jet at take off = 105 m/s

Minimum length of runway = 1312.5 m = 1.312 km

Explanation:

Answer 2

$\huge\tt\blue{u = 0 \: m/s } \\ \huge\tt\blue{a = 3 \: {m/s}^{2} } \\ \huge\tt\blue{t = 35 \: {sec}^{s} } \\ \huge\bf\green{s = to \: find \: out } \\ \huge\bf\green{v = to \: find \: out }$

$\huge\bf\pink{Formula \: to \: apply}$

$\huge\mathfrak\red{s \: = \: at \: + \frac{1}{2} {at}^{2} }$

$\small\mathfrak\blue{s = 0 \times 35 + \frac{1}{2} \times 3 \times {(35)}^{2} } \:$

$\small\mathfrak\blue{s = 0 + \frac{1}{2} \times 3 \times {(35)}^{2} }$

$\small\mathfrak\blue{s = 0 + \frac{1}{2} \times 3 \times 1225}$

$\small\mathfrak\blue{s = \frac{1}{2} \times 3675}$

$\small\mathfrak\blue{s = 1837.5 \: m} \: \: \: \: \: \: \small\mathfrak\blue{(point \: to \: remember)}$

$\small\bf\pink{ \: again \: Formula \: to \: apply }$

$\huge\mathfrak\red{v = u \: + \: at}$

$\small\mathfrak\green{v = 0 + 3 \times 35}$

$\small\mathfrak\green{105 \: m/s} \: \: \: \: \: \: \: \: \huge\bf\blue{answer... }$

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