Question

A jet plane starts from rest with an acceleration of 3ms-2 and makes a run for 35s before taking off. What is the minimum length of the runway and what is the velocity of the jet at take off?.

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Answer 1

Answer:

We should apply s=ut+1/2at^.As the plane starts from rest the initial velocity of the plane will be zero.Then just put the above answers to calculate s(distance).Then use v=u+at to find velocity.

Answer 2

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Given,

Acceleration of the jet=3m/s²,

Time of rum=35seconds

To Find,

Minimum length of runway ,

Velocity of the jet.

Solution,

Here initial velocity, u=0

Acceleration, a=3m/s²

Time, t=35sec

So, to find out the length of the runway during take off,

S=ut+1/2at²

=0×35+1/2×3×35²

=1/2×3×1225

=1/2×3675

=1837.5m

Then, velocity of the plane while taking off,

V=u+at

 =0+3×35

 =105m/s

Hence, length of the runway is 1837.5m and the velocity of the jet at take off is 105m/s.