A jet plane starts from rest with an acceleration of 3ms-2 and makes a run for 35s before taking off. What is the minimum length of the runway and what is the velocity of the jet at take off?.
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Answer:
Initial speed of airplane u=0 m/s
Acceleration of the plane a=3.2 m/s
2
and time taken t=3.28 s
Using formula, distance covered S=ut+
2
1
at
2
⇒ S=0(32.8)+0.5(3.2)(32.8)
2
=1721.3∼1720m
yaar jo bhi hota hai acche ke liye hota hai
Explanation:
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