Question

A jet plane starts from rest with an acceleration of 3ms-2 and makes a run for 35s before taking off. What is the minimum length of the runway and what is the velocity of the jet at take off?.


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Answer 1

Answer:

Explanation:

Let’s start,

Acceleration = 3 units

Time = 35s

Initial velocity = 0 units

Using s=ut+0.5a(t^2)

So,

Distance

=0.5*a*t*t (Because u=0)

=0.5*3*35*35=0.5*3*1225=1837.5 metres =1.8375 km