Question

a jewellery has a bar of 18 carrot b gold and 12 carrot gold .how much of each m must be melted together to obtain a bar of 16 carrot gold weighing 120 gm (pure 24 carrot)​

Answer 1

Answer:

$your \: answer \: is \: 80gm \: and \: 40gm$

Step-by-step explanation:

$let \: x \: gm \: of \: 18 \: gold \: and \: let \: y \: gm \: of \: 12carat \: gold \: \\ x + y = 120 \: \: \: \: \: \: \: \: - (1) \\ \\ the \: purity \: of \: 18 \: carat \: gold \: \: \: \: \: \frac{18}{24} \times 100\% \\ \frac{3}{4} \times 100 = 75\% \\ purity \: of \: 12 \: carot \: gold = \frac{16}{24} \times 100\% \\ \frac{2}{3} \times 100 = \frac{200}{3} \%$