A jewellery shop owner conducts his business in the
following manner. Every once in a while he raises
his prices by a certain percentage and a while later
he reduces his prices by the same percentage. After
one such updown cycle of increasing and then
decreasing his price by x%, the price of a jewel
decreases by 100. In the next cycle, he increases
and then decreases his price by (x/2)% and then
sells the jewel for 2376. What is the initial price of
the jewel (in )?
(B) 2475
(D) 2575
(A) 2450
(C) 2500
Answers
Answered by
0
Answer:
A
2756.25
⇒ Let the original price be P and X%=a
⇒ P−P×(1+a)(1−a)=441
⇒ P×a
2
=441 ---- ( 1 )
⇒ Again, P×[(1+a)(1−a)]
2
=1944.81
⇒ P×(1−a
2
)
2
=1944.81 ----- ( 2 )
Dividing ( 2 ) by ( 1 ). we get,
⇒
P×(a
2
)
P×(1−a
2
)
2
=
441
1944.81
⇒
a
2
(1−a
2
)
2
=4.41
⇒
a
1−a
2
=2.1 [Taking square root on both sides]
∴ a=
5
2
⇒ P×(
5
2
)
2
=441 [Substituting value in ( 1 )]
⇒ P=
4
441×25
=Rs.2756.25
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