Question

a jocker cap is in the form of a right circular cone of radius 7cm and height 27cm.find the area of the sheet required to make 10 such caps​

Answer 1

Answer:

The sheet required for making of 10 such caps is ₹6160cm²

Step-by-step explanation:

Question says that,

A joker cap is in right circular cone with radius 7cm and height 27cm.

Find the area of sheet required to make 10 such caps.

Step 1 : Find the slant height

slant height is given by :

→ l = √r² + h²

Where,

• r(radius) = 7cm.
• h(height) = 27cm.

→ l = √7² + 27²

→ l = √49 + 729

→ l = √778

→ l = 27.89

→ l = 28cm (approx.)

Step 2 : Calculate the C. S. A. of the cap

C. S. A. of the cap is given by :

→ πrl

• Taking ‘π’ as 22/7

→ 22/7 × 7 × 28

→ 22 × 28

→ 616cm²

Step 3 : Calculate the C. S. A. for 10 such caps

We know that,

Required sheet for 10 such caps = 10 × C. S. A.

Or,

➛ 10 × 616

➛ 6160cm²

Hence,the sheet required for making of 10 such caps is 6160cm²

Answer 2

Question :

a jocker cap is in the form of a right circular cone of radius 7cm and height 27cm.find the area of the sheet required to make 10 such caps

Formula used :

l²=h²+r²

where l is slant height , h is the height and r is the radius

CSA of cone = πrl

solution :

Given Radius =7 cm and height =27 cm

Given Radius =7 cm and height =27 cmThen slant height l= √(27)² +(7)²

=729+49

=729+49

= 778

= 778

=27.84 cm

=27.84 cmThen curved surface area conical cap = π×r×l=

= 22/7 ×7×27.84

=612.48m²

Then sheet required for make 10 caps =

= 612.48×10

=6124.8 m