Question

A joggar moves 500 in 2minutes and 1000m in 30s on the same straight path. What is his average speed and average velocity

Answer 1

☣ GIVEN ☣

A jogger moves 500 m in 2 minutes and next 1000 m in 30 seconds on the same straight path.

☣ TO FIND ☣

The average speed and the average velocity of the jogger.

☣ FORMULAS TO BE USED ☣

▪ Average speed = Total distance covered/Total time taken

▪ Average velocity = Overall displacement/Total time taken

☣ SOLUTION ☣

As the jogger moves in a straight path without taking any U-turns or changing its direction, so displacement = distance.

⇒Displacement/Time = Distance/Time

⇒Velocity = Speed

⇒Average velocity = Average speed

$\rule{150}2$

Now,

◙ Total length of the path covered = 500 + 1000 = 1500 m

◙ Total time taken = (2 × 60) + 30 = 120 + 30 = 150 s

Average velocity = Average speed = 1500/150

⇒Average velocity = Average speed = 10 m/s

Therefore, the average speed of the jogger is same as the average velocity of the jogger, that is 10 m/s.

Answer 2

GIVEN

A joggar moves 500 in 2minutes and 1000m in 30s on the same straight path.

TO FIND

What is his average speed and average velocity?

SOLUTION

Total distance covered

= 1000+500 = 1500m

Total time taken

= 2*60 + 30

= 120 + 30 = 150s

Now

Average speed

= total distance travelled/time taken

→ Average speed = 500+1000/120+30

→ Average speed = 1500/150 = 10m/s

★ A jogger moves in straight path

So, Average speed = Average velocity

Hence average velocity same as average speed i.e 10m/s